Which specific makes/models currently provide the best quality and are most trouble-free? Cost is less of a concern than quality and ease of installation. Thanks.

They all kind of stink. Trying to get them to broadcast to other rooms… well, I don’t think you’ll find one. At least not one that is legal. They’re really meant for 6 feet or less.

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A small firm produces both AM and AM/FM car radios. The AM radios take 15 h to produce, and the AM/FM radios take 20h. The number of production hours is limited to 300 h per week. The plant’s capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 AM radios and at least 3 AM/FM radios be produced per week. Write a system of inequalities representing this situation. Then, draw a graph of the feasible region given these conditions, in which x is the number of AM radios and y the number of AM/FM radios.

Do your own homework!!

The number of production hours is limited to 300h per week.The plants capacity is limited to a total of 18 radios per week,and existing orders require that atleast 4am radios and atleast 3 Am/Fm radios be produced per week.Write a system of inequalities representing this situation.

You’re asking for inequalities and my brain says this:
I’m gonna use these symbols <= => for less than or equal to and greater than or equal to as i don’t have that symbol available.

x=am radios y=fm/am radios
15x+20y <=300
x+y<=18
x>=4
y>=3

that’s them all.

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I’m talking about phones which don’t already have FM radios built in. Any kinds of programs out there that can do this?

check with http://www.mobiledownloads4u.webs.com

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A small firm produces both AM and AM/FM car radios. The AM radios take 15 h
to produce, and the AM/FM radios take 20 h. The number of production hours is
limited to 300 h per week. The plant’s capacity is limited to a total of 18 radios per
week, and existing orders require that at least 4 AM radios and at least 3 AM/FM
radios be produced per week. Write a system of inequalities representing this situation.
Then, draw a graph of the feasible region given these conditions, in which x
is the number of AM radios and y the number of AM/FM radios.

Let x= the number of AM radios and y= the number of AM/FM radios produced. You need inequality equations for the production hours, the number of radios produced and the minimum number of radios produced.

15x + 20y ≤ 300
x + y ≤ 18
x ≥ 4
y ≥ 3

I would draw the graph but I don’t know how to do that on here. To find the point of where the inequalities cross solve this system of equations:
15x+20y=300
x+y=18
This works out to 12 AM and 6 AM/FM radios per week.

I have a 1986 Ford LTD,and I just replaced the alternator and voltage regulator. I have one of those old AM/FM dial radios. After I swapped out those two electrical components, my FM signal pickup is very weak. I used be able to pick up about twenty stations, now I can pick up one, and only when the car is idling. After I stop idling, I lose the station mostly, and the static revs up with the motor. Any ideas?

something in your wiring is either
crossed or touching…